思路：倒序单调栈。弹出所有 ≤ 当前身高的元素（这些人都能被看到），count 为弹出数量；若栈非空，还能看到栈顶（第一个更高的人），故 +1。能看到的人数 = count + (栈非空 ? 1 : 0)。
Despite the 2984's lackluster success, IBM moved on. I don't think IBM was
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第八十八条 违反关于社会生活噪声污染防治的法律法规规定，产生社会生活噪声，经基层群众性自治组织、业主委员会、物业服务人、有关部门依法劝阻、调解和处理未能制止，继续干扰他人正常生活、工作和学习的，处五日以下拘留或者一千元以下罚款；情节严重的，处五日以上十日以下拘留，可以并处一千元以下罚款。
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